Course Curriculum
13:29:30
Instructor: Zahid
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Topic:
Class 8 Math Chapter -4.2 , Part-01
Solved Examples on Cubic Equation Formula
Question 1: Solve x3 – 6x2 + 11x – 6 = 0
Solution: This equation can be factorized to give
Solution: This equation can be factorized to give
(x-1)(x-2)(x-3)=0
This equation has three real roots, all different – the solutions are x = 1, x = 2 and x = 3.
Question 2: Solve the cubic equation x3 – 23x2 + 142x – 120.
Solution: First factorize the polynomial to get;
x3 – 23x2 + 142x – 120 = (x – 1) (x2 – 22x + 120)
But x2 – 22x + 120 = x2 – 12x – 10x + 120
= x (x – 12) – 10(x – 12)
= (x – 12) (x – 10)
Therefore, x3 – 23×2 + 142x – 120 = (x – 1) (x – 10) (x – 12)
Equate each factor to zero to get;
Course Curriculum
13:29:30
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